Regex Mismatch: Searching Anywhere For Certain Number Of Digits

I am trying to match values that come in this format: , ####-####-####-####### , ####-########-##### , ######-###-#-###-##-#-#### , ##-####-#####-#-###### For example: 2018-03-10,

Solution 1:

data = '2018-03-10, 354687-56987-314, 2018123-02-10-2019, 10-20-20232316'
re.findall(r'[^, ]*\d{5,}[^,]*',data)

Out[847]: ['354687-56987-314', '2018123-02-10-2019', '10-20-20232316']

EDIT

from the examples given the regex \S*\d{5,}[^,\s]* can be used

Solution 2:

import re
text = "2018-03-10, 2018123-02-10-2019, 10-20-20232316"
re.findall(r'\w+(?:-\w+)+',text)

Solution 3:

Try the following regex. This will capture anything with 5 or more consecutive digits.

r'.*(\d{5,}).*'